ГДЗ Математика 5 класс Мерзляк. Задание 778 онлайн ответы и бесплатный решебник

7 \frac{14}{15} + 2 \frac{1}{15}

9 \frac{24}{27} + 12 \frac{13}{27}

1 - \frac{12}{19}

8 - 3 \frac{6}{15}

12 - 11 \frac{6}{11}

16 \frac{3}{13} - 6 \frac{8}{13}

13 \frac{4}{9} - 2 \frac{8}{9}

10 \frac{7}{16} - 4 \frac{12}{16}

29 \frac{49}{53} - 8 \frac{49}{53}

(20 \frac{16}{25} + 13 \frac{9}{25}) - (23 \frac{4}{14} + 7 \frac{13}{14})

7 \frac{14}{15} + 2 \frac{1}{15} = (7 + 2) + (\frac{14}{15} + \frac{1}{15}) = 9 + \frac{15}{15} = 9 + 1 = 10

9 \frac{24}{27} + 12 \frac{13}{27} = (9 + 12) + (\frac{24}{27} + \frac{13}{27}) = 21 + \frac{37}{27} = 21 + \frac{27}{27} + \frac{10}{27} = 22 \frac{10}{27}

1 - \frac{12}{19} = \frac{19}{19} - \frac{12}{19} = \frac{7}{19}

8 - 3 \frac{6}{15} = 7 \frac{15}{15} - 3 \frac{6}{15} = (7 - 3) + (\frac{15}{15} - \frac{6}{15}) = 4 + \frac{9}{15} = 4 \frac{9}{15}

12 - 11 \frac{6}{11} = 11 \frac{11}{11} - 11 \frac{6}{11} = (11 - 11) + (\frac{11}{11} - \frac{6}{11}) = \frac{5}{11}

16 \frac{3}{13} - 6 \frac{8}{13} = 15 \frac{16}{13} - 6 \frac{8}{13} = (15 - 6) + (\frac{16}{13} - \frac{8}{13}) = 9 + \frac{8}{13} = 9 \frac{8}{13}

13 \frac{4}{9} - 2 \frac{8}{9} = 12 \frac{13}{9} - 2 \frac{8}{9} = (12 - 2) + (\frac{13}{9} - \frac{8}{9}) = 10 + \frac{5}{9} = 10 \frac{5}{9}

10 \frac{7}{16} - 4 \frac{12}{16} = 9 \frac{23}{16} - 4 \frac{12}{16} = (9 - 4) + (\frac{23}{16} - \frac{12}{16}) = 5 + \frac{11}{16} = 5 \frac{11}{16}

29 \frac{49}{53} - 8 \frac{49}{53} = (29 - 8) + (\frac{49}{53} - \frac{49}{53}) = 21 + 0 = 21

(20 \frac{16}{25} + 13 \frac{9}{25}) - (23 \frac{4}{14} + 7 \frac{13}{14}) = ((20 + 13) + (\frac{16}{25} + \frac{9}{25})) - ((23 + 7) + (\frac{4}{14} + \frac{13}{14})) = (33 + \frac{25}{25}) - (30 + \frac{17}{14}) = 34 - 31 \frac{3}{14} = 33 \frac{14}{14} - 31 \frac{3}{14} = (33 - 31) + (\frac{14}{14} - \frac{3}{14}) = 2 \frac{11}{14}

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